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SQL to Display fields of two tables in tabular form

Oracle Database Tips by Donald BurlesonDecember 18,  2015

 

Question (By Imran ahmad):  I have two tables and I want to see the fields of both tables in columns-Wise pattern(with sorting), so I can see which fields are common.  In other words, I want to display(DESC) the fields of both tables in tabular form.

Answer (By Laurent Schneider):  I would do a full outer join  on the column name:

select t1.column_name ADDRESS, t2.column_name ADDRESS_DETAIL
from
  (select column_name from user_tab_columns where table_name='ADDRESS') t1
  full outer join  
  (select column_name from user_tab_columns where table_name='ADDRESS_DETAIL') T2
on (t1.column_name=t2.column_name)
order by 1
;

Also see these related notes:

  1. Oracle SQL: displaying multiple columns per row

  2. Display Oracle SQL output rows on one single line

  3. SQL to compare rows within two tables

  4. Converting Oracle rows to columns

Another solution to display columns from two tables in tabular form:

SQL> DESC TABLE1
Name                                      Null?    Type
----------------------------------------- -------- ----------------------------
A                                                  NUMBER(38)
B                                                  NUMBER(38)
C                                                  NUMBER(38)
D                                                  NUMBER(38)

SQL> DESC TABLE2
Name                                      Null?    Type
----------------------------------------- -------- ----------------------------
C                                                  NUMBER(38)
D                                                  NUMBER(38)
E                                                  NUMBER(38)
F                                                  NUMBER(38)

SQL> SELECT t1.column_name, t2.column_name
  2    FROM (SELECT *
  3       FROM user_tab_columns
  4      WHERE table_name = 'TABLE1') t1
  5    FULL OUTER JOIN
  6         (SELECT *
  7               FROM user_tab_columns
  8              WHERE table_name = 'TABLE2') t2
  9      ON t1.column_name = t2.column_name
10   ORDER BY t1.column_name
11  /

COLUMN_NAME                    COLUMN_NAME
------------------------------ ------------------------------
A
B
C                              C
D                              D
                               E
                               F

6 rows selected.



 

 

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